Datastructurethroughcindepthbydeepalisrivastavapdfrapidshare

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Datastructurethroughcindepthbydeepalisrivastavapdfrapidshare

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What i want is to count the number of occurrences of € (€), € (€) and £ (£) into file1.txt and file2.txt.
I’ve tried using awk, but the output doesn’t make sense. The problem is that, with this code, I get twice the number of results.
awk -F’|’ -v RS=’\|[
\r\t]*’ ‘{seen[$1]++} END {for (i in seen) if (seen[i] == 1) print i; else print “Error”}’ file.txt
What i want is that, for example, I get for file1.txt only the occurences of € (€) and £ (£) and for file2.txt only the occurences of € (€) and € (€) but not the £ (£). This way i can just copy and paste the results.
Can someone help me please?

A:

You do not really need AWK, let me show how to do it with Bash:
#!/usr/bin/env bash

# -*- shell-script -*-

# create a set from the separator characters
# this set will contain the separators we want to find
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A:

You can do so with a simple compare function:
struct foo {
char * str1;
int str2;
};

int compare_by_str(const void * a, const void * b)
{
const foo * const fa = (const foo*) a;
const foo * const fb = (const foo*) b;

return strcmp(fa->str1, fb->str1);
}

int compare_by_int(const void * a, const void * b)
{
const foo * const fa = (const foo*) a;
const foo * const fb = (const foo*) b;

return fa->str2 – fb->str2;
}

int compare_by_both(const void * a, const void * b)
{
const foo * const fa = (const foo*) a;
const foo * const fb = (const foo*) b;

return (compare_by_str(fa->str1, fb->str1) str1 = “a”;
x->str2 = 3;

foo * y = (foo*) malloc(sizeof(foo));
y->str1 = “a”;
y->str2 = 9;

printf(“%s %d
“, x->str1, x->str2);
printf(“%s %d
“, y->str1, y->str2);
printf(“%s %d
“, x, y);

int ret = compare_by_both(&x, &y

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